Top 350+ Solved Design of Steel Structures MCQ Questions Answer

From 91 to 105 of 402

Q. When the upper column does not provide full bearing area over lower column, the column splice is provided with the following assumption

a. Bearing plate is assumed as a short beam to transmit the axial load to the lower column section

b. Axial load is assumed to be taken by flanges

c. Load transmitted from the flanges of upper column and reactions from the flanges of lower columns are equal and form a couple

d. All the above

  • d. All the above

Q. For the economical design of a combined footing to support two equal column loads, the projections of beams in lower tier are kept such that bending moment under column is equal to

a. Bending moment at the centre of the beam

b. Half the bending moment at the centre of the beam

c. Twice the bending moment at the centre of the beam

d. None of these

  • a. Bending moment at the centre of the beam

Q. The allowable shear stress in the web of mild steel beams decreases with (Where 'h is thickness)

a. Decrease in h/t ratio

b. Increase in h/t ratio

c. Decrease in thickness

d. Increase in height

  • b. Increase in h/t ratio

Q. On eccentrically loaded columns, the equivalent axial load may be obtained by

a. Adding the axial load, eccentric load, the product of the bending moment due to eccentric load and the appropriate bending factor

b. Adding the axial load and eccentric load and subtracting the product of bending moment and appropriate bending factor

c. Dividing the sum of axial load and eccentric load by the product of the bending moment and appropriate bending factor

d. None of these

  • a. Adding the axial load, eccentric load, the product of the bending moment due to eccentric load and the appropriate bending factor

Q. When the bolts are subjected to reversal of stresses, the most suitable type of boltis

a. Black bolt

b. Ordinary unfinished bolt

c. Turned and fitted bolt

d. High strength bolt

  • d. High strength bolt

Q. The size of a butt weld is specified by the effective throat thickness which in the case of incomplete penetration, is taken as

a. ½ of the thickness of thicker part

b. ¾ of the thickness of thicker part

c. ¾ of the thickness of thinner part

d. 7/8 of the thickness of thinner part

  • d. 7/8 of the thickness of thinner part

Q. In a built up section carrying a tensile force, the flanges of two channels are turnedoutward

a. To simplify the transverse connections

b. To minimise lacing

c. To have greater lateral rigidity

d. All the above

  • c. To have greater lateral rigidity

Q. Modified moment of inertia of sections with a single web, is equal to moment of inertia of the section about Y-Y axis at the point of maximum bending moment and is multiplied by the ratio of

a. Area of compression flange at the minimum bending moment to the corresponding area at the point of maximum bending moment

b. Area of tension flange at the minimum bending moment of the corresponding area atthe point of maximum bending moment

c. Total area of flanges at the maximum bending moment to the corresponding area at the point of maximum bending moment

d. None of these

  • c. Total area of flanges at the maximum bending moment to the corresponding area at the point of maximum bending moment

Q. The live load for a sloping roof with slope 15°, where access is not provided toroof, is taken as

a. 0.65 kN/m²

b. 0.75 kN/m²

c. 1.35 kN/m²

d. 1.50 kN/m²

  • a. 0.65 kN/m²

Q. Pick up the correct statement from the following:

a. Dead load includes self-weight of the structure and super-imposed loads permanently attached to the structure

b. Dead loads change their positions and vary in magnitude

c. Dead loads are known in the beginning of the design

d. None of these

  • a. Dead load includes self-weight of the structure and super-imposed loads permanently attached to the structure

Q. If N is the number of rivets in the joint, the strength of a riveted joint againstshearing of rivets, is given by

a. Ps = N d2 × Ps

b. Ps = N × (d × t × ps)

c. Ps = N × (p - d) × t × Ps

d. Ps = N × (P + d) × t × ps

  • a. Ps = N d2 × Ps

Q. The sway bracing is designed to transfer

a. 2Vi % of the top panel wind load to bottom bracing

b. 10% of the top panel wind load to bottombracing

c. 25% of the top panel wind load to bottombracing

d. 50% of the top panel wind load to bottom bracing

  • d. 50% of the top panel wind load to bottom bracing
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