Q. With usual notations the depth of the neutral axis of a balanced section, is given by (Solved)
1. mc/t = (d -n)/n
2. t/mc = (d -n)/n
3. t/mc = (d + n)/n
4. mc/t = n/(d - n)
- d. mc/t = n/(d - n)
1. mc/t = (d -n)/n
2. t/mc = (d -n)/n
3. t/mc = (d + n)/n
4. mc/t = n/(d - n)