Q. What is the output of the following piece of code?#mod1def change(a): b=[x*2 for x in a] print(b)#mod2def change(a): b=[x*x for x in a] print(b)from mod1 import changefrom mod2 import change#mains=[1,2,3]change(s) (Solved)

1. [2,4,6].

2. [1,4,9].

3. [2,4,6].

4. There is a name clash

  • d. There is a name clash
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