Q. If the moment of inertia of a section about its axis is and its effective sectional area is, its radius of gyration r about the axis, is (Solved)
1. r = I/A
2. r I/A)
3. r = (I/A)
4. r A/I)
- b. r I/A)
1. r = I/A
2. r I/A)
3. r = (I/A)
4. r A/I)