Q. If the moment of inertia of a section about its axis is and its effective sectional area is , itsradius of gyration r about the axis, is (Solved)
1. r = i/a
2. r i/a)
3. r = (i/a)
4. r a/i)
- b. r i/a)
1. r = i/a
2. r i/a)
3. r = (i/a)
4. r a/i)