Q. The Fourier series for the function f (x) = sin2x is (Solved)
1. 0.5 + 0.5 sin 2x
2. 0.5 – 0.5 sin 2x
3. 0.5 + 0.5 cos 2x
4. 0.5 – 0.5 cos 2x
- d. 0.5 – 0.5 cos 2x
1. 0.5 + 0.5 sin 2x
2. 0.5 – 0.5 sin 2x
3. 0.5 + 0.5 cos 2x
4. 0.5 – 0.5 cos 2x