Q. In a push - pull converter, the filter capacitor can be obtained as (Solved)
1. Cmin = V / ( Vr L f2 )
2. Cmin= ( 1 – D ) V / ( Vr L f2 )
3. Cmin= ( 1 – 2 D ) V / 32 ( Vr L f2 )
4. Cmin= ( 1 – 2 D ) V / 42 ( Vr L f2 )
- c. Cmin= ( 1 – 2 D ) V / 32 ( Vr L f2 )