Q. In heat transfer, conductance equals conductivity (kcal/hr/sqm/°C/cm) dividedby (Solved)
1. hr (time)
2. sqm (area)
3. °C (temperature)
4. cm (thickness)
5. kcal (heat).
- d. cm (thickness)
1. hr (time)
2. sqm (area)
3. °C (temperature)
4. cm (thickness)
5. kcal (heat).